Reverse in a range

1 <= N <= 10^5
1 <= A[i] <= 10^9
0 <= B <= C <= N - 1

The first argument A is an array of integer.
The second and third arguments are integers B and C

Return the array A after reversing in the given range.

Input 1:
A = [1, 2, 3, 4]
B = 2
C = 3

Input 2:
A = [2, 5, 6]
B = 0
C = 2

Output 1:
[1, 2, 4, 3]

Output 2:
[6, 5, 2]

Explanation 1:
We reverse the subarray [3, 4].

Explanation 2:
We reverse the entire array [2, 5, 6].

public class ReverseInRange {
 
    public static int[] reverseRange(int[] A, int B, int C) {
        while (B < C) {
            int temp = A[B];
            A[B] = A[C];
            A[C] = temp;
            B++;
            C--;
        }
        return A;
    }
 
    public static void main(String[] args) {
        int[] arr1 = {1, 2, 3, 4};
        int[] result1 = reverseRange(arr1, 2, 3);
        System.out.print("Output 1: ");
        for (int num : result1) {
            System.out.print(num + " ");
        }
        System.out.println();
 
        int[] arr2 = {2, 5, 6};
        int[] result2 = reverseRange(arr2, 0, 2);
        System.out.print("Output 2: ");
        for (int num : result2) {
            System.out.print(num + " ");
        }
        System.out.println();
    }
}

def reverse_range(A, B, C):
    while B < C:
        A[B], A[C] = A[C], A[B]
        B += 1
        C -= 1
    return A
 
arr1 = [1, 2, 3, 4]
result1 = reverse_range(arr1, 2, 3)
print("Output 1:", result1)
 
arr2 = [2, 5, 6]
result2 = reverse_range(arr2, 0, 2)
print("Output 2:", result2)

function reverseRange(A, B, C) {
    while (B < C) {
        let temp = A[B];
        A[B] = A[C];
        A[C] = temp;
        B++;
        C--;
    }
    return A;
}
 
let arr1 = [1, 2, 3, 4];
let result1 = reverseRange(arr1, 2, 3);
console.log("Output 1:", result1);
 
let arr2 = [2, 5, 6];
let result2 = reverseRange(arr2, 0, 2);
console.log("Output 2:", result2);